How to use [[UIApplication sharedApplication] openURL:] open other app?

QQGuang · 05-25-2011, 05:49 AM

Hi All,

I followed Launching Your Own Application via a Custom URL Scheme instruction to open app1(GlassButton) within app2(FontTest).

The open method of FontTest as following:

-(void)open {

BOOL res = [[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"glassbutton://"]];

if (res) {

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"glassbutton://"]];
}

}

The value of "res" is "YES", but nothing happen after openURL method be called. The info-list of "FontTest"as following:

URL Schemes: glassbutton

URL identifier: com.yourcompany.glassbutton

I tried to open twitter and facebook apps by "twitter://" and "fb://" successfully. But I do not know why I cannot open this small app. I'm not sure whether any thing/step wrong or missing? Need I handle - (BOOL)application

UIApplication *)application handleOpenURL

NSURL *)url for FontTest, if yes, how to handle it? Could you please kindly help me? Thanks in advance!

dany_dev · 05-25-2011, 06:20 AM

but glassbutton is a your app right? and you setted all the things for the protocol on glassbutton, right?

QQGuang · 05-25-2011, 08:01 AM

Quote:

Originally Posted by dany_dev

but glassbutton is a your app right? and you setted all the things for the protocol on glassbutton, right?

Hi dany_dev,

Yes, "glassbutton" is a small app. What protocol need be set in "glassbutton"? Sorry, I have no clue for this issue. Could you please provide more detail info about it? Thanks!

dany_dev · 05-25-2011, 08:07 AM

i said "protocol" but i mean custom url scheme.

However the question is not "glassbutton is a smal app or a big app"

.

You can run another app only if that app support it, so if the app use custom url scheme. So I asked, "glassbutton is a your app? are you sure that you correctly wrote the code to handle custom url scheme?".

If glassbutton is NOT a your app and doesn't provide custom url scheme, so you will be not able to run it.

alpatel2007 · 11-20-2011, 09:20 AM

I create one page in html5 and open it in uiwebview(browser) xcode. I open flashapp1 through url scheme (using uiapplication sharedapplication).
n. It's open well. but how can i return html5 page(webview). when i click home button pressed, flashapp close but not return my html page returned.
Give me any idea?.

HTML5 page here.
<html>
<a href="flashapp1://">Open Flash App1</a><br />
<a href="flashapp2://">Open Flash App2</a>
</html>