What is the most efficient way to change an UIImageView image property?

[joe_mac_112283]

Say I have this code:

UIImage *image = [[UIImage alloc] initWithContentsOfFile:[[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"pic.png"]];

imageView.image = image;
[image release];

That would be the most efficient way to display an image. However, what if I wanted to change the image property? Do I simply replace it like so:

imageView.image = newImage;
[newImage release];

Or will that cause memory leaks? Should I release the UIImageView and allocate and initialize it?

This memory management stuff is confusing...

Thank you.

[LittleX1]

This won't cause a memory error. If you check the UIKit Framework for the UIImageView.h file you will see the property-declaration of .image:

@property(nonatomic,retain) UIImage *image;

If you're familiar with accessor-methods you will know what happens to the image that was saved in your image view before.

If my memory serves me well, "@property (nonatomic, retain) ..." means:

- (void) setImage:(UIImage *)newImage {
if (newImage != image) {
[image release];
[newImage retain];
}