Setting UIButton cornerRadius

[cal30biz]

I am trying to create a UIButton that has rounded corners, but that I can alter the background color at runtime. Using background images is not an option.

I am using a UIButton set to Custom so that the background color will show (not just the corners) am using the following to set the cornerRadius:

 

	NSInteger max = [myButtonArray count];
	
	for(int i=0; i<max; i++)
	{
		UIButton *button = (UIButton *)[myButtonArray objectAtIndex:i];
		button.layer.cornerRadius=SMALL_LABEL_CORNER_RADIUS;
	}
}

I am getting the error:

"Accessing unknown 'cornerRadius' component of a property

Yet, I know there is a .layer.cornerRadius available as I have used it in the past, within this very iPhone app.

What am I missing here?

[lkdpham]

Make sure you #import <QuartzCore/QuartzCore.h>

Originally Posted by cal30biz

I am trying to create a UIButton that has rounded corners, but that I can alter the background color at runtime. Using background images is not an option.

I am using a UIButton set to Custom so that the background color will show (not just the corners) am using the following to set the cornerRadius:

 

	NSInteger max = [myButtonArray count];
	
	for(int i=0; i<max; i++)
	{
		UIButton *button = (UIButton *)[myButtonArray objectAtIndex:i];
		button.layer.cornerRadius=SMALL_LABEL_CORNER_RADIUS;
	}
}

I am getting the error:

"Accessing unknown 'cornerRadius' component of a property

Yet, I know there is a .layer.cornerRadius available as I have used it in the past, within this very iPhone app.

What am I missing here?

[gammapoint]

This works:

[[aButton layer] setCornerRadius:4.0f];
[[aButton layer] setMasksToBounds:YES];
[[aButton layer] setBorderWidth:1.0f];