Images Loading in Wrong Spot

[Samalope]

Hello we have been working with an array to get a random image to display on the screen when a button is pressed.
This works, and everytime the button is pressed, a random image from our set is displayed.
However, the image always seems to display in the top left corner of the view, where we are trying to get it in the center of the screen.
We are trying to connect it up with a UIImage view, which is connected along with the view itself to a second view controller- whether that is what we are supposed to do or not, we dont know haha.
So if there is a bit of code to center the displayed image or place it IN a UIImage view, we would appreciate help.

Here is our code when the button is clicked:

(IBAction)startClickid)sender
{
[start removeFromSuperview];

myArray = [[NSMutableArray alloc] init];
[myArray addObject:[UIImage imageNamed:@"1.png"]];
[myArray addObject:[UIImage imageNamed:@"2.png"]];
[myArray addObject:[UIImage imageNamed:@"0.png"]];

start = [[UIImageView alloc] initWithImage:[myArray objectAtIndexarc4random() % [myArray count])]];
[self.view addSubview:start];
[start release];

}

also, as a bonus, would anyone be able to tell us how to make it so the randomized images are not displayed twice.
(so it would show 1,3,4,2 or somthing like that as opposed to 1,1,1,2,2,4,3,2, etc.)

[mr-sk]

Can you resize the ImageView in IB so that it lives in the center of the screen?
Have you tried that? Can you include a screen shot of your IB layout?

[smasher]

You should be able to set the position of your view with something like this:

start.center.x=320/2;
start.center.y=460/2;

UIView Class Reference

[Samalope]

Originally Posted by smasher

You should be able to set the position of your view with something like this:

start.center.x=320/2;
start.center.y=460/2;

UIView Class Reference

Hi-
we tried that but it does not work here is a screen shot of IB. It is not loading in the UIImageView Pictured.

[smasher]

Ah. The code you posted creates a brand new UIImageView and attaches it to the current view. If you're trying to display the image in an existing UIImageView, do this:

myArray = [[NSMutableArray alloc] init];
[myArray addObject:[UIImage imageNamed:@"1.png"]];
[myArray addObject:[UIImage imageNamed:@"2.png"]];
[myArray addObject:[UIImage imageNamed:@"0.png"]];

existingImageView.image = [myArray objectAtIndex: arc4random() % [myArray count]];

You should replace "existingImageView" with the name of the IBOutlet connected to your imageview.

[Samalope]

Originally Posted by smasher

Ah. The code you posted creates a brand new UIImageView and attaches it to the current view. If you're trying to display the image in an existing UIImageView, do this:

myArray = [[NSMutableArray alloc] init];
[myArray addObject:[UIImage imageNamed:@"1.png"]];
[myArray addObject:[UIImage imageNamed:@"2.png"]];
[myArray addObject:[UIImage imageNamed:@"0.png"]];

existingImageView.image = [myArray objectAtIndex: arc4random() % [myArray count]];

You should replace "existingImageView" with the name of the IBOutlet connected to your imageview.

We did not catch that Thank you again for helping us! Oh yeah and we are going to give you a promo code to try our app out when we are done in a few days (if apple will approve)!