How to define an array of IBOutlet??

waynechiu · 03-15-2009, 03:05 AM

I am trying to define an array of IBOutlet UIButton but it fail.
IBOutlet UIButton *myButton[3];
@property (nonatomic, retain) UIButton **myButton;

are OK. Don't have any compiler error but
@synthesize myButton; give me an error and also I don't see the myButton in the File's Owner of Interface Builder.

Slayer5150 · 03-15-2009, 09:08 AM

Quote:

Originally Posted by waynechiu

I am trying to define an array of IBOutlet UIButton but it fail.
IBOutlet UIButton *myButton[3];
@property (nonatomic, retain) UIButton **myButton;

are OK. Don't have any compiler error but
@synthesize myButton; give me an error and also I don't see the myButton in the File's Owner of Interface Builder.

I'm not sure if it should work or not, but you would need to synthesize *(myButton), *(myButton+1) and *(myButton+2).

PhoneyDeveloper · 03-15-2009, 02:58 PM

You can't really do it that way. Properties don't work with arrays and you can't make the outlet be assigned to an offset into an array. It might be possible to do this with a union but I've never tried that.

If what you want is an array of buttons then use an NSArray and set the tags of the buttons in IB. Then add the buttons to the array based on the tags in viewDidLoad.

Also, if it's really only three buttons then just have three outlets. I don't think that's a big deal.